知道三个物理量,求剩余两个物理量
| 编号 | 已知量 | 求 | 公式 |
|---|---|---|---|
| 1 | \(v_0、v_t、a\) | \(x\) | \(v_t^2-v_0^2=2ax\) ☀️ |
| 2 | \(v_0、v_t、a\) | \(t\) | \(v_t=v_0+at\) ☀️ |
| 3 | \(v_0、x、a\) | \(v_t\) | \(v_t^2-v_0^2=2ax\) ☀️ |
| 4 | \(v_0、v_t、t\) | \(x\) | \(x=\frac{v_0+v_t}{2}t\) ☀️ |
| 5 | \(v_0、a、t\) | \(v_t\) | \(v_t=v_0+at\) ☀️ |
| 6 | \(v_0、a、t\) | \(x\) | \(x=v_0t+\frac{1}{2}at^2\) ☀️ |
| 7 | \(v_t、a、t\) | \(x\) | \(x=v_tt-\frac{1}{2}at^2\) ☀️ |
| 8 | \(v_0、v_t、x\) | \(a\) | \(v_t^2-v_0^2=2ax\) ☀️ |
| 9 | \(v_0、v_t、x\) | \(t\) | \(x=\frac{v_0+v_t}{2}t\) ☀️ |
| 10 | \(v_0、v_t、t\) | \(a\) | \(v_t=v_0+at\) ☀️ |
| 11 | \(v_t、x、t\) | \(v_0\) | \(x=\frac{v_0+v_t}{2}t\) ☀️ |
| 12 | \(v_t、x、a\) | \(t\) | \(x=v_tt-\frac{1}{2}at^2\) ☀️ |
| 13 | \(v_t、a、t\) | \(v_0\) | \(v_t=v_0+at\) ☀️ |
| 14 | \(v_0、x、t\) | \(v_t\) | \(x=\frac{v_0+v_t}{2}t\) ☀️ |
| 15 | \(v_t、x、a\) | \(v_0\) | \(v_t^2-v_0^2=2ax\) ☀️ |
| 16 | \(v_0、x、t\) | \(a\) | \(x=v_0t+\frac{1}{2}at^2\) ☀️ |
| 17 | \(x、a、t\) | \(v_0\) | \(x=v_0t+\frac{1}{2}at^2\) ☀️ |
| 18 | \(x、a、t\) | \(v_t\) | \(x=v_tt-\frac{1}{2}at^2\) ☀️ |
| 19 | \(v_0、x、a\) | \(t\) | \(x=v_0t+\frac{1}{2}at^2\) ☀️ |
| 20 | \(v_t、x、t\) | \(a\) | \(x=v_tt-\frac{1}{2}at^2\) ☀️ |
有“零速度”,初速度或者末速度为零,知道二个物理量,求剩余两个物理量
关键词:静止开始,最后停下来,刹车等
| 编号 | 已知量 | 求 | 公式 |
|---|---|---|---|
| 1 | \(v、a\) | \(x\) | \(v^2=2ax\) ☀️ |
| 2 | \(v、a\) | \(t\) | \(v=at\) ☀️ |
| 3 | \(x、a\) | \(v\) | \(v^2=2ax\) ☀️ |
| 4 | \(v、t\) | \(x\) | \(x=\frac{v}{2}t\) ☀️ |
| 5 | \(a、t\) | \(v\) | \(v=at\) ☀️ |
| 6 | \(a、t\) | \(x\) | \(x=\frac{1}{2}at^2\) ☀️ |
| 7 | \(v、x\) | \(a\) | \(v^2=2ax\) ☀️ |
| 8 | \(v、x\) | \(t\) | \(x=\frac{v}{2}t\) ☀️ |
| 9 | \(v、t\) | \(a\) | \(v=at\) ☀️ |
| 10 | \(x、t\) | \(v\) | \(x=\frac{v}{2}t\) ☀️ |
| 11 | \(x、a\) | \(t\) | \(x=\frac{1}{2}at^2\) ☀️ |
| 12 | \(a、t\) | \(v\) | \(v=at\) ☀️ |
| 13 | \(x、t\) | \(v\) | \(x=\frac{v}{2}t\) ☀️ |
| 14 | \(x、a\) | \(v\) | \(v^2=2ax\) ☀️ |
| 15 | \(x、t\) | \(a\) | \(x=\frac{1}{2}at^2\) ☀️ |
| 16 | \(x、a\) | \(t\) | \(x=\frac{1}{2}at^2\) ☀️ |
自由落体或者竖直上抛,有“零速度”,加速度已知a=g,相当于两个物理量已经知道了,只需要再知道一个物理量,就可以求剩余两个物理量
关键词:自由落体,竖直上抛等
| 编号 | 已知量 | 求 | 公式 |
|---|---|---|---|
| 1 | \(v\) | \(h\) | \(v^2=2gh\) ☀️ |
| 2 | \(v\) | \(t\) | \(v=gt\) ☀️ |
| 3 | \(t\) | \(h\) | \(h=\frac{1}{2}gt^2\) ☀️ |
| 4 | \(h\) | \(v\) | \(v^2=2gh\) ☀️ |
| 5 | \(t\) | \(v\) | \(v=gt\) ☀️ |
| 6 | \(h\) | \(t\) | \(h=\frac{1}{2}gt^2\) ☀️ |