1.专题01直线运动(答案)
(1)、\(1m/s^2\)
(2)、\(4\)
(1)、\(20m/s\)
(2)、\(680m\)
2.专题02相互作用(答案)
3.专题03运动与力的关系(答案)
(1)、\(5.0\)
(2)、\(失重\);\(1.0\)
(1)、B
(2)、B
(3)、远大于;系统误差;C
(4)、\(\frac{x_6-x_4}{10T}\);\(A\)
(4)、较大、较小\(\frac{x_6-x_4}{10T}\);\(A\)
(5)、
(6)、远大于钩码质量 ;解析略
(1)、D
(2)、B
(3)、反比;槽码
4.专题04曲线运动(答案)
(1)、相同
(2)、
(3)、0.71
(1)、\(4m/s\);\(\frac{1}{3}s\)
(2)、\(\frac{5}{9}m\)
(1)、\(\frac{\mu g}{\omega_1^2r_1}\)
(2)、\(\sqrt{\frac{\mu g\sin\theta\cos\beta}{(\sin\theta\sin\beta+\mu\cos\theta)r_2}}\)
5.专题05万有引力与宇宙航行(答案)
6.专题06机械能守恒定律(答案)
(1)450N
(2)9.0×\(10^3\)J
(3)600W
(1)1200N,900N
(2)-4200J
7.专题07动量守恒定律(答案)
(1)>
(2)\(m_{a}x_{P}=m_{a}x_{M}+m_{b}x_{N}\),小球离开斜槽末端后做平抛运动,竖直方向高度相同故下落时间相同,水平方向匀速运动直线运动,小球水平飞出时的速度与平抛运动的水平位移成正比。
(1)1.0
(2)0.20
(3)B
(1)\(v_1=\frac{\left(m+M\right)v_0-Mv}m\)
(2)\(F=\frac{M\left(v-v_0\right)}{\Delta t}\)
(1)\(\tan\theta=\frac{ma}{mg+F_N}\)
①330N∙s,方向竖直向上
②0.2m
(1)40N
(2)4m/s
(3)0.15
(1)5m/s
(2)0.3J
(3)0.2m
(1)5m/s
(2)0.3J
(3)0.2m
(1)1m/s,1m/s
(2)0.2
(3)0.12J
(1)6N
(2)4m/s
(3)\(0.25\leq\mu<0.4\)
(1)v=4m/s
(2)m=1kg,\(\mu = 0.2\)
(3)L=4.5m
(1)1.5m
(2)90J,2
(3)\(x_{AC}=\frac74L_B\)
(1)\(v=\frac{m_\mathrm{A}v_0}{m_\mathrm{A}+m_\mathrm{B}}\)
\(F=\frac{m_\mathrm{A}^2v_0^2}{\left(m_\mathrm{A}+m_\mathrm{B}\right)R}\)
(2)\(\frac{m_\mathrm{A}}{m_\mathrm{B}}=2\text{ 或 }\frac{m_\mathrm{A}}{m_\mathrm{B}}=5\)
(3)\(\frac{2\pi Rm_\mathrm{A}}{m_\mathrm{A}+m_\mathrm{B}}\cdot\frac{e^{2n}-1}{e^{2n}\left(e-1\right)}\)
8.专题08机械振动与机械波(答案)
(1)7.54或7.55或7.56
(2)10
(3)A
(4)见解析
(5)线性的
(6)0.120kg
(7)负方向
(1)\(\frac{t}{30}\)
(2)\(l_{0}+\frac{gT^{2}}{4\pi^{2}}\)
(3)9.59
(4)AB
(1)摆长
(2)1.06
(3)\(x=\frac{gT^2}{144\pi}\cos\left(\frac{2\pi}Tt\right)\)
9.专题09静电场(答案)
(1)\(\frac{2kQ}{R^2}\)、大于、大于
(1)\(\frac{1}{5000}\)
(2)15.0
(3)2
(4)\(4.7 \times 10^3\)、2.8
(1)\(\frac{U}{L}\)
(2)\(\nu_A=\sqrt{\frac{Uq-mgL}m}\)
\(\nu_B=\sqrt{\frac{3\left(Uq-mgL\right)}m}\)
10.专题10恒定电流(答案)
(1)M
(2)4000
(3)\(R_{\mathrm{g}}=\frac{U}{I}-R_{1}-R_{2}\)
(4)A
(5)0.86
(1)1.23、12.3
(4)右
(5)小于
(1)320
(2)\(R_2\)
(3)②
(4)最右端
(5)错误,解析略
(1)CAB;负极、正级;×100;1.6
(2)\(R_1,a\)
(3)\(\frac{UR_0}{U_1-U}\)
(4)1.57
(1)
(3)a
(6)1.40、17
(2)
(4)kdh、高
(5)0.46
(1)2.450
(2)1
(3)1.91
(4)大于
(1)
(2)b、1.60、较大
(3)逆时针、\(U_{l}{=}U_{2}\)
(1)C
(2)0.5、3.1
(1)A
(2)\(\frac{1}{b}\)
(3)\(\frac{R_0}{n-1}\)
(1)①1.0
②\(I(r+R_{\mathrm{A}})\)
③\(1.40\)、\(1.0\)
(2)D
(1)\(\frac{\nu^2}{2g\left(\sin\theta+\mu\cos\theta\right)}\)
(2)\(mgv(\sin\theta+\mu\cos\theta)\)
(3)\(\frac{\sin\theta}{\sin\theta+\mu\cos\theta}\)
11.专题11磁场(答案)
(1)带正电,\(\frac{E_1^2}{2UB_1^2}\)
(2)\(\frac{4UB_{1}}{E_{1}B_{2}}\)
(3)\(\frac{2E_2-E_1}{B_1}\)
(1)\(\frac{2m\nu_0}{Be}\)
(2)\(\sqrt{2}\)
(3)\(U\leq-\frac{mv_0^2\cos^2\theta}{2e}\)
(4)见解析
(1)\(B=\frac{m\nu_0}{2qL}\)
(2)\(d=\frac32\pi L\)
(3)\(F=\frac{q\omega}{3\nu_0}\cdot\Delta x\)
(1)\(\frac{2\pi m\nu_0}{eL}\)
(2)\(\frac{2\pi r}L\)
(3)\(\frac{2\pi^2r^2\nu_0^2m}{EeL^2}\)
(1)\(\frac{\sqrt{2}m\nu_0}{Bq}\)、\(\frac{2\pi m}{Bq}\)
(2)\(E=\sqrt{2}B\nu_{0}\)
(3)\(\frac{\left(2-\sqrt{2}\right)m\nu_0}{Bq}\)
(1)\(U_0=\frac{qB^2L^2}{8m}\)
(2)\(E=\frac{qB^2L}{4m}\),方向沿x轴正方向
(3)\(\left(\frac{3-\sqrt{3}}{12}L,\frac{\sqrt{3}}3L+\frac{\pi L\left(4n+3\right)}8\right)(n=0,1,2\cdots)\)
(1)正电;\(q=\frac{\pi m}{Bt_0}\)
(2)\(D=\sqrt{\frac{3\pi t_0U_0}{8B}}\);\(v=\pi\sqrt{\frac{\pi U_0}{24Bt_0}}\)
(3)\(W=\frac{\pi mU_0\left(\pi^2+16\right)}{48Bt_0}\)
12.专题12电磁感应(答案)
(1)\(\frac{mg}{k}\)
(2)\(\frac{4\nu_0r^2\pi^2B^2}R\)
(3)\(\frac16\Big(m\nu_0^2-kA_1^2\Big)\)
(1)\(kL^2\cdot t\)、\(kL^2\)、从a流向b
(2)\(F_\text{安}=\frac{k^2L^3t}{R+art^2}\)
(3)\(\frac{\mu k^2L^3}{2\sqrt{Rar}}+m\big(g+a\big)\)
(1)\(v=\frac{v_0}2\)
(2)\(U=\frac{BLv_0}4\)、\(W=\frac{CB^{2}L^{2}{v_{0}}^{2}}{8}\)
(1)\(BL\sqrt{2gL}\)
(2)\(\frac{B^2L^2\sqrt{2gL}}{3mR}\)
(3)\(\frac{B^2L^3+mR\sqrt{2gL}}{B^2L^2}\)
(1)\(a_{乙0}=2\mathrm{m/s^2}\),方向水平向右
(2)\(d\geq24\mathrm{m}\)
(3)\(\frac{356}{11}m\lt d \lt \frac{696}{11}m\)
(1)\(F_{\max}=\frac{B^2L^3\omega}R\),\(F_{\min}=\frac{B^2L^3\omega}{2R}\)
(2)\(\frac a{g\cos\theta}-\frac13\tan\theta \)
13.专题13交变电流传感器(答案)
C、3、1.8
(1)负极
(2)①A、A、D或C
②减小
(3)增大
见解析
(2)\(I=\sqrt{\frac{\pi-\beta}\pi}\cdot\frac{15nBr^2\omega}{2R}\)
(3)\(\frac{225n^2B^2r^4\omega^2\left(\pi-\beta\right)}{2\pi R}\)
14.专题14光学电磁波相对论(答案)
小于、逆时针
(1)B
(2)大
(3)>
(1)B
(2)1.57
(3)不变
(1)平衡摩擦力、2.86
(2)4.108
(3)光源、干涉条纹
\(\sqrt{\frac{1}{4-2\sqrt{2}}}\)
(1)\(\sin\theta=0.75\)
(2)\(0 \lt x\leq\frac{2\sqrt{3}}9R\)
15.专题15热学(答案)
3.0或3
大于
(1)\(2.5 \times 10^5 Pa\)
(2)\(6L\)
(1)\(\frac{pV}{p_0}\)
(2)\(5 \times 10^{-3} m^3\)
(1)\(8 \times 10^4 Pa\)
(2)\(4.8 \times 10^{3}N\)
(1)100N
(2)327K
(1)\(2 \times 10^5 Pa\)
(2)\(2.0 m^3\)
(1)\(x=2cm\)
(2)\(V=8.92\times10^{-4}m^3\)
(1)50N
(2)见解析
(3)
(1)\(0.9 \times 10^5 Pa\)
(2)\(3.6 \times 10^{-2} m^3\)
(3)\(110kg\)
(1)\(p_A=\frac45p_0\)、\(p_B=\frac23p_0\)
(2)\(k=\frac{8p_0S}{15l}\)
(1)气体从状态1到状态2是不可逆过程,分子平均动能不变
(2)10N
(3)\(89.3J\)
(1)\(\frac{U_{\mathfrak{m}}^2}{50R}\)
(2)\(\frac{50CT_0R}{U_\mathrm{m}^2}\)
(1)\(\frac65T_0\)
(2)\(\frac15h(p_0S+mg)+\frac15CT_0\)